EAX
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例句
All stubs from ntdll. dll start with the line MOV EAX, ServiceIndex, which applies to any version and flavour of Windows NT.
所有来自于ntdll.dll的代理都从一行代码MOVEAX，ServiceIndex开始-它可以适用于任何版本和风味的WindowsNT。
After a few simple tests, the actual system call is invoked using the system_call_table and index contained in eax.
在经过几个简单测试之后，使用system_call_table和eax中包含的索引来执行真正的系统调用了。
The code at BE allocates the memory from the heap for the Singleton object and stores a pointer to that memory in eax.
BE处的代码为Singleton对象从堆中分配内存，并将一个指向该块内存的指针存储到eax中。
This table, shown in Figure 2, uses the index provided in eax to identify which system call to invoke from the table (sys_call_table).
这个表如图2所示，使用eax中提供的索引来确定要调用该表中的哪个系统调用（sys_call_table）。
The next line, C3, takes the pointer in eax and stores it back into the instance reference at memory location 049388C8.
下一行代码，C3，获取eax中的指针并将其存储回内存位置为049388C8的实例引用。
The input to cpuid (the variable "op" ) is passed to "asm" in the eax register, as cpuid expects it to.
对cpuid的输入（变量“op”）传递到“asm”的eax寄存器中，因为cpuid希望它这样做。
Larger structures are returned in the EAX register as pointers to hidden return structures.
如果是体积更大的结构体返回的话，那么EAX存放的将是一个指向结构体所在地址的指针。
A value of 1 (for the Linux exit system call) is stored in EAX to request that the program exit.
EAX中存储的值是1（代表Linuxexit系统调用），这请求程序退出。
Thus %eax serves here as both input and output register.
这样，这里的%eax既可以用作输入寄存器，又可以用作输出寄存器。
And since %eax is specified in the clobbered list, GCC doesn't use it anywhere else to store data.
因为%eax是在修饰列表中指定的，GCC不在任何其它地方使用它来存储数据。
The service code is present in the EAX register.
服务编码放在EAX寄存器中。
Unless this is done, GCC assumes that %eax and %ecx are free, and it may decide to use them for storing other data.
在完成这一步之前，GCC假设%eax和%ecx是自由的，它可能决定将它们用作存储其它的数据。
The first two lines of assembly code at B0 and B5 load the instance reference from memory location 049388C8 into eax and test for null.
B0和B5处的前两行汇编代码将instance引用从内存位置049388C8加载至eax中，并进行null检查。
The CPU chooses the AL, AX, or EAX register depending on the width of the operand (8, 16, or 32 bits).
CPU根据操作数的宽度（8、16或32）选择AL、AX或EAX寄存器。
While lodsl modifies %eax, the lodsl and stosl instructions use it implicitly.
当lodsl修改%eax时，lodsl和stosl指令隐含地使用它。
And here you can see another constraint that uses the two registers %eax and %edx to combine two 32-bit values and generate a 64-bit value
在下面可以看到另一个约束，它使用两个寄存器%eax和%edx将两个32位的值合并在一起，然后生成一个64位的值
