dwords

dwords

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例句

No. The variants are not strongly typed and the execution options are not enumerations, but generic DWORDs.

显然不是variants不是类型执行参数没有定义枚举类型而是整数

In keeping with the MASM32 practice of "loose" type checking, function parameters are just defined as DWORDs.

为了保持MASM32松散类型检查原则函数参数只是定义DWORD

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